Partition Pruning
Partition pruning is a performance optimization that applies to partitioned tables. It analyzes the filter conditions in query statements, and eliminates (prunes) partitions from consideration when they do not contain any data that will be required. By eliminating the non-required partitions, TiDB is able to reduce the amount of data that needs to be accessed and potentially significantly improving query execution times.
The following is an example:
CREATE TABLE t1 (
id INT NOT NULL PRIMARY KEY,
pad VARCHAR(100)
)
PARTITION BY RANGE COLUMNS(id) (
PARTITION p0 VALUES LESS THAN (100),
PARTITION p1 VALUES LESS THAN (200),
PARTITION p2 VALUES LESS THAN (MAXVALUE)
);
INSERT INTO t1 VALUES (1, 'test1'),(101, 'test2'), (201, 'test3');
EXPLAIN SELECT * FROM t1 WHERE id BETWEEN 80 AND 120;
+----------------------------+---------+-----------+------------------------+------------------------------------------------+
| id | estRows | task | access object | operator info |
+----------------------------+---------+-----------+------------------------+------------------------------------------------+
| PartitionUnion_8 | 80.00 | root | | |
| ├─TableReader_10 | 40.00 | root | | data:TableRangeScan_9 |
| │ └─TableRangeScan_9 | 40.00 | cop[tikv] | table:t1, partition:p0 | range:[80,120], keep order:false, stats:pseudo |
| └─TableReader_12 | 40.00 | root | | data:TableRangeScan_11 |
| └─TableRangeScan_11 | 40.00 | cop[tikv] | table:t1, partition:p1 | range:[80,120], keep order:false, stats:pseudo |
+----------------------------+---------+-----------+------------------------+------------------------------------------------+
5 rows in set (0.00 sec)
Usage scenarios of partition pruning
The usage scenarios of partition pruning are different for the two types of partitioned tables: Range partitioned tables and Hash partitioned tables.
Use partition pruning in Hash partitioned tables
This section describes the applicable and inapplicable usage scenarios of partition pruning in Hash partitioned tables.
Applicable scenario in Hash partitioned tables
Partition pruning applies only to the query condition of equality comparison in Hash partitioned tables.
create table t (x int) partition by hash(x) partitions 4;
explain select * from t where x = 1;
+-------------------------+----------+-----------+-----------------------+--------------------------------+
| id | estRows | task | access object | operator info |
+-------------------------+----------+-----------+-----------------------+--------------------------------+
| TableReader_8 | 10.00 | root | | data:Selection_7 |
| └─Selection_7 | 10.00 | cop[tikv] | | eq(test.t.x, 1) |
| └─TableFullScan_6 | 10000.00 | cop[tikv] | table:t, partition:p1 | keep order:false, stats:pseudo |
+-------------------------+----------+-----------+-----------------------+--------------------------------+
In the SQL statement above, it can be known from the condition x = 1 that all results fall in one partition. The value 1 can be confirmed to be in the p1 partition after passing through the Hash partition. Therefore, only the p1 partition needs to be scanned, and there is no need to access the p2, p3, and p4 partitions that will not have matching results. From the execution plan, only one TableFullScan operator appears and the p1 partition is specified in access object, so it can be confirmed that partition pruning takes effect.
Inapplicable scenarios in Hash partitioned tables
This section describes two inapplicable usage scenarios of partition pruning in Hash partitioned tables.
Scenario one
If you cannot confirm the condition that the query result falls in only one partition (such as in, between, >, <, >=, <=), you cannot use the partition pruning optimization. For example:
create table t (x int) partition by hash(x) partitions 4;
explain select * from t where x > 2;
+------------------------------+----------+-----------+-----------------------+--------------------------------+
| id | estRows | task | access object | operator info |
+------------------------------+----------+-----------+-----------------------+--------------------------------+
| Union_10 | 13333.33 | root | | |
| ├─TableReader_13 | 3333.33 | root | | data:Selection_12 |
| │ └─Selection_12 | 3333.33 | cop[tikv] | | gt(test.t.x, 2) |
| │ └─TableFullScan_11 | 10000.00 | cop[tikv] | table:t, partition:p0 | keep order:false, stats:pseudo |
| ├─TableReader_16 | 3333.33 | root | | data:Selection_15 |
| │ └─Selection_15 | 3333.33 | cop[tikv] | | gt(test.t.x, 2) |
| │ └─TableFullScan_14 | 10000.00 | cop[tikv] | table:t, partition:p1 | keep order:false, stats:pseudo |
| ├─TableReader_19 | 3333.33 | root | | data:Selection_18 |
| │ └─Selection_18 | 3333.33 | cop[tikv] | | gt(test.t.x, 2) |
| │ └─TableFullScan_17 | 10000.00 | cop[tikv] | table:t, partition:p2 | keep order:false, stats:pseudo |
| └─TableReader_22 | 3333.33 | root | | data:Selection_21 |
| └─Selection_21 | 3333.33 | cop[tikv] | | gt(test.t.x, 2) |
| └─TableFullScan_20 | 10000.00 | cop[tikv] | table:t, partition:p3 | keep order:false, stats:pseudo |
+------------------------------+----------+-----------+-----------------------+--------------------------------+
In this case, partition pruning is inapplicable because the corresponding Hash partition cannot be confirmed by the x > 2 condition.
Scenario two
Because the rule optimization of partition pruning is performed during the generation phase of the query plan, partition pruning is not suitable for scenarios where the filter conditions can be obtained only during the execution phase. For example:
create table t (x int) partition by hash(x) partitions 4;
explain select * from t2 where x = (select * from t1 where t2.x = t1.x and t2.x < 2);
+--------------------------------------+----------+-----------+------------------------+----------------------------------------------+
| id | estRows | task | access object | operator info |
+--------------------------------------+----------+-----------+------------------------+----------------------------------------------+
| Projection_13 | 9990.00 | root | | test.t2.x |
| └─Apply_15 | 9990.00 | root | | inner join, equal:[eq(test.t2.x, test.t1.x)] |
| ├─TableReader_18(Build) | 9990.00 | root | | data:Selection_17 |
| │ └─Selection_17 | 9990.00 | cop[tikv] | | not(isnull(test.t2.x)) |
| │ └─TableFullScan_16 | 10000.00 | cop[tikv] | table:t2 | keep order:false, stats:pseudo |
| └─Selection_19(Probe) | 0.80 | root | | not(isnull(test.t1.x)) |
| └─MaxOneRow_20 | 1.00 | root | | |
| └─Union_21 | 2.00 | root | | |
| ├─TableReader_24 | 2.00 | root | | data:Selection_23 |
| │ └─Selection_23 | 2.00 | cop[tikv] | | eq(test.t2.x, test.t1.x), lt(test.t2.x, 2) |
| │ └─TableFullScan_22 | 2500.00 | cop[tikv] | table:t1, partition:p0 | keep order:false, stats:pseudo |
| └─TableReader_27 | 2.00 | root | | data:Selection_26 |
| └─Selection_26 | 2.00 | cop[tikv] | | eq(test.t2.x, test.t1.x), lt(test.t2.x, 2) |
| └─TableFullScan_25 | 2500.00 | cop[tikv] | table:t1, partition:p1 | keep order:false, stats:pseudo |
+--------------------------------------+----------+-----------+------------------------+----------------------------------------------+
Each time this query reads a row from t2, it will query on the t1 partitioned table. Theoretically, the filter condition of t1.x = val is met at this time, but in fact, partition pruning takes effect only in the generation phase of the query plan, not the execution phase.
Use partition pruning in Range partitioned tables
This section describes the applicable and inapplicable usage scenarios of partition pruning in Range partitioned tables.
Applicable scenarios in Range partitioned tables
This section describes three applicable usage scenarios of partition pruning in Range partitioned tables.
Scenario one
Partition pruning applies to the query condition of equality comparison in Range partitioned tables. For example:
create table t (x int) partition by range (x) (
partition p0 values less than (5),
partition p1 values less than (10),
partition p2 values less than (15)
);
explain select * from t where x = 3;
+-------------------------+----------+-----------+-----------------------+--------------------------------+
| id | estRows | task | access object | operator info |
+-------------------------+----------+-----------+-----------------------+--------------------------------+
| TableReader_8 | 10.00 | root | | data:Selection_7 |
| └─Selection_7 | 10.00 | cop[tikv] | | eq(test.t.x, 3) |
| └─TableFullScan_6 | 10000.00 | cop[tikv] | table:t, partition:p0 | keep order:false, stats:pseudo |
+-------------------------+----------+-----------+-----------------------+--------------------------------+
Partition pruning also applies to the equality comparison that uses the in query condition. For example:
create table t (x int) partition by range (x) (
partition p0 values less than (5),
partition p1 values less than (10),
partition p2 values less than (15)
);
explain select * from t where x in(1,13);
+-----------------------------+----------+-----------+-----------------------+--------------------------------+
| id | estRows | task | access object | operator info |
+-----------------------------+----------+-----------+-----------------------+--------------------------------+
| Union_8 | 40.00 | root | | |
| ├─TableReader_11 | 20.00 | root | | data:Selection_10 |
| │ └─Selection_10 | 20.00 | cop[tikv] | | in(test.t.x, 1, 13) |
| │ └─TableFullScan_9 | 10000.00 | cop[tikv] | table:t, partition:p0 | keep order:false, stats:pseudo |
| └─TableReader_14 | 20.00 | root | | data:Selection_13 |
| └─Selection_13 | 20.00 | cop[tikv] | | in(test.t.x, 1, 13) |
| └─TableFullScan_12 | 10000.00 | cop[tikv] | table:t, partition:p2 | keep order:false, stats:pseudo |
+-----------------------------+----------+-----------+-----------------------+--------------------------------+
In the SQL statement above, it can be known from the x in(1,13) condition that all results fall in a few partitions. After analysis, it is found that all records of x = 1 are in the p0 partition, and all records of x = 13 are in the p2 partition, so only p0 and p2 partitions need to be accessed.
Scenario two
Partition pruning applies to the query condition of interval comparison，such as between, >, <, =, >=, <=. For example:
create table t (x int) partition by range (x) (
partition p0 values less than (5),
partition p1 values less than (10),
partition p2 values less than (15)
);
explain select * from t where x between 7 and 14;
+-----------------------------+----------+-----------+-----------------------+-----------------------------------+
| id | estRows | task | access object | operator info |
+-----------------------------+----------+-----------+-----------------------+-----------------------------------+
| Union_8 | 500.00 | root | | |
| ├─TableReader_11 | 250.00 | root | | data:Selection_10 |
| │ └─Selection_10 | 250.00 | cop[tikv] | | ge(test.t.x, 7), le(test.t.x, 14) |
| │ └─TableFullScan_9 | 10000.00 | cop[tikv] | table:t, partition:p1 | keep order:false, stats:pseudo |
| └─TableReader_14 | 250.00 | root | | data:Selection_13 |
| └─Selection_13 | 250.00 | cop[tikv] | | ge(test.t.x, 7), le(test.t.x, 14) |
| └─TableFullScan_12 | 10000.00 | cop[tikv] | table:t, partition:p2 | keep order:false, stats:pseudo |
+-----------------------------+----------+-----------+-----------------------+-----------------------------------+
Scenario three
Partition pruning applies to the scenario where the partition expression is in the simple form of fn(col), the query condition is one of >, <, =, >=, and <=, and the fn function is monotonous.
If the fn function is monotonous, for any x and y, if x > y, then fn(x) > fn(y). Then this fn function can be called strictly monotonous. For any x and y, if x > y, then fn(x) >= fn(y). In this case, fn could also be called "monotonous". Theoretically, all monotonous functions, strictly or not, are supported by partition pruning. Currently, TiDB only supports the following monotonous functions:
unix_timestamp
to_days
For example, partition pruning takes effect when the partition expression is in the form of fn(col), where the fn is monotonous function to_days:
create table t (id datetime) partition by range (to_days(id)) (
partition p0 values less than (to_days('2020-04-01')),
partition p1 values less than (to_days('2020-05-01')));
explain select * from t where id > '2020-04-18';
+-------------------------+----------+-----------+-----------------------+-------------------------------------------+
| id | estRows | task | access object | operator info |
+-------------------------+----------+-----------+-----------------------+-------------------------------------------+
| TableReader_8 | 3333.33 | root | | data:Selection_7 |
| └─Selection_7 | 3333.33 | cop[tikv] | | gt(test.t.id, 2020-04-18 00:00:00.000000) |
| └─TableFullScan_6 | 10000.00 | cop[tikv] | table:t, partition:p1 | keep order:false, stats:pseudo |
+-------------------------+----------+-----------+-----------------------+-------------------------------------------+
Inapplicable scenario in Range partitioned tables
Because the rule optimization of partition pruning is performed during the generation phase of the query plan, partition pruning is not suitable for scenarios where the filter conditions can be obtained only during the execution phase. For example:
create table t1 (x int) partition by range (x) (
partition p0 values less than (5),
partition p1 values less than (10));
create table t2 (x int);
explain select * from t2 where x < (select * from t1 where t2.x < t1.x and t2.x < 2);
+--------------------------------------+----------+-----------+------------------------+-----------------------------------------------------------+
| id | estRows | task | access object | operator info |
+--------------------------------------+----------+-----------+------------------------+-----------------------------------------------------------+
| Projection_13 | 9990.00 | root | | test.t2.x |
| └─Apply_15 | 9990.00 | root | | CARTESIAN inner join, other cond:lt(test.t2.x, test.t1.x) |
| ├─TableReader_18(Build) | 9990.00 | root | | data:Selection_17 |
| │ └─Selection_17 | 9990.00 | cop[tikv] | | not(isnull(test.t2.x)) |
| │ └─TableFullScan_16 | 10000.00 | cop[tikv] | table:t2 | keep order:false, stats:pseudo |
| └─Selection_19(Probe) | 0.80 | root | | not(isnull(test.t1.x)) |
| └─MaxOneRow_20 | 1.00 | root | | |
| └─Union_21 | 2.00 | root | | |
| ├─TableReader_24 | 2.00 | root | | data:Selection_23 |
| │ └─Selection_23 | 2.00 | cop[tikv] | | lt(test.t2.x, 2), lt(test.t2.x, test.t1.x) |
| │ └─TableFullScan_22 | 2.50 | cop[tikv] | table:t1, partition:p0 | keep order:false, stats:pseudo |
| └─TableReader_27 | 2.00 | root | | data:Selection_26 |
| └─Selection_26 | 2.00 | cop[tikv] | | lt(test.t2.x, 2), lt(test.t2.x, test.t1.x) |
| └─TableFullScan_25 | 2.50 | cop[tikv] | table:t1, partition:p1 | keep order:false, stats:pseudo |
+--------------------------------------+----------+-----------+------------------------+-----------------------------------------------------------+
14 rows in set (0.00 sec)
Each time this query reads a row from t2, it will query on the t1 partitioned table. Theoretically, the t1.x> val filter condition is met at this time, but in fact, partition pruning takes effect only in the generation phase of the query plan, not the execution phase.